Introduction to Cryptography - Part A
In a (3, 7) Shamir secret sharing scheme with modulus 59, three of the shares are (5, 11), (10, 43) and (20, 34). Another share is (7, k), but the value of k is unreadable. Find the correct value of k
1. Here, the Shamir scheme is (3,7). Here, three shares will be used for finding M as S(x)= M+ si (x).
M + 5.s = 11 (mod 59)
M + 10.s = 43 (mod 59)
M + 20.s = 34 (mod 59)
S(x)= 84- 42(k) (mod 5…
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